(x-3)^2-8=x+1

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Solution for (x-3)^2-8=x+1 equation: 



(x-3)^2-8=x+1

We move all terms to the left:

(x-3)^2-8-(x+1)=0

We get rid of parentheses

(x-3)^2-x-1-8=0

We add all the numbers together, and all the variables

-1x+(x-3)^2-9=0

We move all terms containing x to the left, all other terms to the right

-1x+(x-3)^2=9

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